the sum of the first six term of an ap is 42 the ratio of its 10th term to its 30th term is 1 ratio 3 find the first term of the AP
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given:-Sn=42
Nth term of an AP are in ratio (T10:T30=1:3) but the series are same so there would be same first term or C.D. from there we can find the relation of first term and C.D as solve in above paper.
but Sn=42(given) from here we can put those values as obtained previously then obtain the first term as we get the equation.
thanks.
i hope you will be able to understand.
Nth term of an AP are in ratio (T10:T30=1:3) but the series are same so there would be same first term or C.D. from there we can find the relation of first term and C.D as solve in above paper.
but Sn=42(given) from here we can put those values as obtained previously then obtain the first term as we get the equation.
thanks.
i hope you will be able to understand.
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