Question

The sum of the first six terms of an
AP is 48 and the common difference is 2
what is the 4th term


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Answer 1

See the pic below for solution. Hope it helps you.kindly mark it as brainliest.

Answer 2

The 4th term of an A.P is 9.

Formula

Sum of 'n' term of an A.P

The sum of AP's first n terms is the sum(addition) of the arithmetic sequence's first n terms.

It is equal to n divided by 2 times the product of the difference between the second and first terms-'d' also known as common difference, and  (n-1), where n is the number of terms to be added.

$S_{n} =\frac{n}{2} [2a+(n-1)d]$

nth term of an A.P

An AP's nth term is sometimes referred to as the AP's general term.

$a_{th} =a+(n-1)d$

Given:

The sum of the first six terms of an AP is 48.

The common difference is 2.

Total number of terms in A.P is 6.

Explanation:

Put the value of sum, common difference and first term in the sum formula.

Calculate the value of first term 'a'.

$48 =\frac{6}{2} [2a+(6-1)2]$

Solving equation for the value of a.

First term $a=3$.

Put the value of a = 3, d = 2, n = 4 in nth formula and calculate 4th term.

$a_{4} =3=(4-1)2$

$a_{4} =9$

Thus the 4th term of an A.P is $a_{4} =9$.

To know more about sum of an A.P, here

https://brainly.in/question/80961?msp_poc_exp=2

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