The sum of the first six terms of ap,✓2,√8,√18,.........Is....
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Given AP is ✓2,√8,√18,........
that is ✓2, 2✓2, 3✓2, ........
Here first term a = ✓2 and common difference d = 2✓2- ✓2 = ✓2
So sum of first six terms is
S₆ = 6/2 [2(✓2)+(6-1)✓2] [ usin Sn = n/2 [2a+(n-1)d] ]
⇒ S₆ = 3[2✓2+5✓2]
⇒ S₆ = 3(7✓2)
⇒ S₆ = 21√2
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