Question

The sum of the first term of an ap is 1050 and first term is 10 find d

Answer 1

Answer:

ANSWER

S14=1050

a=10

Sn=2n[2a+(n−1)d]

1050=214[2×10+(14−1)d]

71050=[20+14d−d]

150−20=13d

130=13d

d=10

The 20th term is

a20=a+(n−1)d

=10+(20−1)10

⇒10+190

a20⇒200