the sum of the first three numbers in an AP is 42 and the product of the product of the first and third term is 52. find the first term and the common difference.
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(a-d)+a+(a+d)=42
3a=42
<<<<<a=14>>>>>>
(a+d)(a-d)=52
a^{2} -d^{2} =52
196-d^{2}=52
196-52=d^{2}
<<<<d=12>>>>>
ayushi10500:
Don't you think that d will be -12 and +12 ?
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"The terms be a-3d,a-d, a+d,a+3d
Aggregate = 4*a = 44.
a = 11;
Item
( a-3d)(a+3d) = 140
11*11-9*d*d = 140
d*d = - 19/9.
Negative. No genuine regular distinction.
The significance of ' outrageous' is vital.
The AP has multiple terms.
a,a+d,a+2d,a+3d,… .,a+(n-1)d.
Aggregate condition
4a + 6d = 44
2a + 3d = 11 eqn-1
Item condition this is the answer."
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