CBSE BOARD X, asked by harishpl110, 1 year ago

the sum of the first three numbers in an AP is 42 and the product of the product of the first and third term is 52. find the first term and the common difference.

Answers

Answered by traghavendrara
0

(a-d)+a+(a+d)=42

3a=42

<<<<<a=14>>>>>>

(a+d)(a-d)=52

a^{2} -d^{2} =52

196-d^{2}=52

196-52=d^{2}

<<<<d=12>>>>>


ayushi10500: Don't you think that d will be -12 and +12 ?
traghavendrara: +12
Answered by aqibkincsem
0

"The terms be a-3d,a-d, a+d,a+3d

Aggregate = 4*a = 44.

a = 11;

Item

( a-3d)(a+3d) = 140

11*11-9*d*d = 140

d*d = - 19/9.

Negative. No genuine regular distinction.

The significance of ' outrageous' is vital.

The AP has multiple terms.

a,a+d,a+2d,a+3d,… .,a+(n-1)d.

Aggregate condition

4a + 6d = 44

2a + 3d = 11 eqn-1

Item condition this is the answer."

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