Question

The sum of the first three term of an AP is 33. If the product of the first and the third term exceeds the second term by 29,then find the AP

Answer 1

let the three terms of A.P are a-d,a,a+d
so
a-d+a+a+d=33
3a=33
a=11

A.T.Q
(a-d)(a+d)-11=29
(11-d)(11+d)-11=29
121-d square-11=29
d=9

a-d=11-9=2
a=11
a+d=11+9=20
A.P=2,11,20

Answer 2

Answer:

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