Question

the sum of the first three term of the AP is -24 sum of the next 3 terms is 12, sum of the last 13 term is 252 find the term.​

Answer 1

Answer:

Given,

a=12,d=6,a

n

=252

a

n

=a+(n−1)d

252=12+(n−1)6

40=n−1

∴n=41

S

n

=

2

n(a+a

n

)

=

241(12+252)

=5412