Question

the sum of the first three terms of a GP is 16 and the sum of the next three terms is 128.Then the first term,common ratio and to n terms of the GP respectively​

Answer 1

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Answer 2

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crankybirds30

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Answer:

Let first term be a and common ratio be r.

So sum is a/(1−r)=x

For other series sum is a2/(1−r2)=y

So y/x2=(1−r)/(1+r)

So by componendo and dividendo

r=(x2−y)/(x2+y)