Question

the sum of the first three terms of an A.P is 24 and the sum of their square is 224 find the 1st three terms​

Answer 1

Answer:

let the roots of A.P be (a-d),a,(a+d)

now the sum of A.P is 24 that means

a-d+a+a+d =24

3a =24

a=8

we got the value of a=8

now squaring the terms

(a-d)2 +(a)2 + (a+d)2=224

where2 are square not in multiplication

a2 +d2-2ad + a2+a2+d2+2ad=224

3a2+2d2=224

3 X 8X8+2d2=224

2d2=224-192

2d2=32

d2=32/2

d2=16

d=4

therefore,a-d,a,a+d

8-4,8,8+4

4,8,12 thia is the value of first three terms

HOPE IT HELPFULL