Question

The sum of the first three terms of an A.P.is 33. If the Product of the first term an
third term exceeds the 2nd term by 29. Find A.P. and also find the sum of first 25 terms.
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Answer 1

Answer:

a-d+a+a+d=33

3a=33

a=11

(a-d)(a+d)-a=29

a^2-d^2-a=29

121_d^2-11=29

d^2=81

d=+-9

ap is2,11,20 or 20,11,2

sum = 2975

Step-by-step explanation:

the sum found by using the formula n/2{2a+(n-1)d}