Question

The sum of the first three terms of an A.P is 33.If the product of the first and the third terms exceeds the secondition term by 29,find the A.P

Answer 1

Heya!!

Let the three terms of the AP be a-d, a and a+d.

Their sum: a-d+a+a+d = 3a = 33 or a = 11.

(a-d)(a+d)= a+29, or

(11-d)(11+d) = 11+29 = 40, or

121 - d^2 = 40, or

d^2 = 121–40 = 81, or

d = 9 or -9.

So the AP is 2, 11 and 20, or 20, 11 and 2.

Hope this helps you ☺☺