The sum of the first three terms of an A.P is 42 & the product of the first and the third term is 52. Find first term and common difference.
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neetapandit150:
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As it is given than S3=42
Let the first term be a
Let the the third term be a3
they given that product of-
a*a3=52
Firstly we apply the formula of sum of 3 no S3
S3=n/2(2a+(n-1)d
42=3/2(2a+2d)
42=3/2*2(a+d). taking 2 common from (2a+2d)
42=3(a+d)
42/3=a+d
14=a+d.......(1).
14-d=a
a(a+2d)=52
putting a value here
(14-d)(14-d+2d)=52
(14-d)(14+d)=52. (a+b)(a-b)=a²-b²
14²-d²=52
196-d²=52
-d²=52-196
-d²=-144
d²=144
d=12... putting this d value in eq(1)
14=a+d
14=a+12
14-12=a
2=a..
Hence common difference=12
First term a=2
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