Question

the sum of the first three terms of an A.P. is 48 . if the product of the first and second terms exceeds four times the third term by 12 ., find the A.P

Answer 1

Let the three terms be a-d,a,a+d

Sum=a-d+a+a+d=48

Solving this, we get

3a=48

a=16

a(a-d)-4(a+d)=12

Keeping the value of a in above equation

16(16-d)-4(16+d)=12

Solving this, we get

d=9

Therefore terms are 7,16,25 (ans)

Answer 2

Answer:

it is a answer of this question