Question

the sum of the first three terms of an ap is 33 if the product of the first term and the term exist the second term by 29 find AP and also find the sum of first 25 term​

Answer 1

Answer:

let three term be a,(a-d),(a+d)

a+(a-d)+(a+d)=33

a-d+a+a+d=33

3a=33

a=11

product of first and third is equal to second + 29

11 - d × 11 + d equal to 11 + 29

121-d^2=40

-d^2=40-121

d^2=81

d=√81=9

Therefore ap is 11 ,20 ,29, 38....

a25=a+(n-1)d

a25=11+(25-1)9

a25=11+24×9

a25=11+216

a25=227