The sum of the first two terms of a GP is 5/3 and the sum of infinity of the series is 3. The common ratio
is
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Given-
Sum of first two terms of GP= 5/3
Sum of infinity series = 3
To find-
common ratio
Solution-
let first term of GP be "a"
and
it's common ratio be "r"
ATQ
Sum of first two terms=
a+ar=5/3
taking a common we get
a(1+r)=5/3 ...(1)
Sum of infinite series=
a/(1-r) = 3 ...(2)
solving equation 1 and 2 we get
a = 5/3(1+r)
5/3(1-r^2)=3
5/9= 1-r^2
r^2= 4/9
r= +_ 2/3
a= 1,5
hence common ration = r = +_ 2/3
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