Question

the sum of the four consecutive numbers in an ap is 32 and the ratio of the product of the first and last term of the product of the two middle terms is 7 ratio 5 find the number​

Answer 1

let a-3d, a-d,a+d and a+3d are in AP

a-3d+a-d+a+d+a-3d=32

4a=32

a=8

Now,

(a-3d)(a+3d)/(a-d)(a+d)=7/5

(a^2-(3d)^2)/(a^2-d^2)=7/5

Answer 2

Mate here is your answer