Question

The sum of the four consecutive numbers in AP is 32 and the ratio of the product of the first and the last terms to the product of two middle terms is 7:15 . Find the numbers.​

Answer 1

Answer:

Soi nahi....................

Answer 2

Step-by-step explanation:

Let the 4 numbers be a-d, a, a+d and a+2d.

ATP,

(a-d) +(a) +(a+d) +(a+2d)= 32 __i.e. sum of the terms.

Therefore we get,

4a+2d = 32

or, 2a+d = 16

or, d = 16- 2a ____ (i)

In the 2nd case,

{(a-d) ×(a+d)}/{(a)×(a+2d)} = 7/15

By putting the value of d from equation (i) we get,

a= 10

d= -4

Therefore,

1st number= a-d = 14

2nd number= a = 10

3rd number= a+d = 6

4th number= a +2d = 2

Here is your answer.

If this was helpful please leave a like and mark me brainliest. It helps me a lot!