Question

The sum of the four consecutive numbers is 350 what will.Be the sum.Of the squares of the largest number and the smallest number

Answer 1

Let the smallest no be x.

∴ No will be x , x+1 , x+2 , x+3.

Adding all these we get 350                                                  ....(Given)

⇒ x + x+1 + x+2 + x+3 = 350

    4x + 6 = 350

→ 4x = 344

∴ x = 86.

Now sum of square of smallest and largest no will be,

⇒ (x)² + (x+3)²

= (8)² + (8+3)²

= 64 + 121

→ 185, is the sum.

Hope it helps.

Cheers!!