The sum of the fourth and twelfth term of an arithmetic progression is 10. What is the sum of the first 30 terms of the arithmetic progression?
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Step-by-step explanation:
The 4th term of an AP is a+3d, the 12th term is a+11d.
According to the question, a+3d+a+11d= 10
Therefore, 2a +14d= 10
a+7d= 5
The sum of the first 30 terms of the AP is
S= 15[2a+29d] Which can be calculated.
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