The sum of the integers from 1 to 100 which are not divisible by 3 or 5 is (a) 2489 (b) 4735 (c) 2317 (d) 2632
Answers
Answered by
3
Answer:
2632
Step-by-step explanation:
s=sum(1-100)- sum (3-99) - sum (5-100) + sum (15-90)
= 5050 - 1683 - 1050 + 315
= 2632
Answered by
0
Answer:
an = a+(n-1)d
last multiple of 3 is 99
99 = 3+(n-1)3
99 = 3+3n-3
n = 99/3 = 33
there are 33 multiples of 3
sum of these are
s₃₃ = a + an
=( 3+99)33/2 =1,683
similarly
95 = 5n
n = 95/5 = 19
s₅₅ = (5+95)55/2= 2,750
sum of both = 2,750+1,683 =4433
Step-by-step explanation:
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