the sum of the interior angle of a polygon is 1440 degree find the number of the side of a polygon
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If the sum of the interior anglesof a regular polygon measures up to 1440 degrees, how many sidesdoes the polygon have? Sum ofInterior Angles of a polygon is 180(n−2) 180 where n n is thenumber of sides. So 180(n−2)=1440 180 ( n − 2 ) = 1440 --> n=10
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(2n-4)×90°=1440
n=(1440/90 +4)/2=10
n=(1440/90 +4)/2=10
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