The sum of the interior angles of a nonagon is − − − − − − − − − −
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The sum of the exterior angles of any polygon is 360.
For a regular nonagon each exterior angle = 360/9 = 40 deg and each interior angle is 180–40 = 140 deg.
The sum of the interior angles of a regular nonagon is thus 9*140 = 1260 deg.
Another approach: Sum of the interior angles of a nonagon = (n-2)* 180 = 7*180 = 1260 deg.
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Answered by
4
Answer:
1260°
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