Question

The sum of the interior angles of a polygon is 1860 than the no of sides of the polygon is​

Answer 1

Step-by-step explanation:

We know that, Sum of measures of all interior angles of polygons =(2n−4)×90

∘

Given, interior angle =1260

∘

1260=(2n−4)×90

∘

1260/90=2n−4

14=2n−4

By transposing we get,

2n=14+4

2n=18

n=18/2

n=9

Therefore, the number of sides in a polygon is 9 .

Answer 2

Answer:

n = 9

Step-by-step explanation:

We know that, Sum of measures of all interior angles of polygons =(2n−4)×90∘

Given, interior angle =1260∘

1260=(2n−4)×90∘

1260/90=2n−4

14=2n−4

By transposing we get,

2n=14+4

2n=18

n=18/2

n=9

Therefore, the number of sides in a polygon is 9 .

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