The sum of the length breadth and height of a cuboid is 38cm and the length of its diagonal is 22cm. find the surface area of the cuboid.
HINT: given L+B+H=38 AND L^+B^+H^=22^
find 2(LB+BH+HL)
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we know under root of l^2+b^2+h^2=lenght of diagonal =22
therefore l^2+b^2+h^2=484
and (l+b+h)^2=l^2+b^2+h^2+2(lb+bh+hl)
1444=484+2(lb+bh+hl)
total surface area =960
therefore l^2+b^2+h^2=484
and (l+b+h)^2=l^2+b^2+h^2+2(lb+bh+hl)
1444=484+2(lb+bh+hl)
total surface area =960
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