Question

The sum of the length,breadth and height of a cuboid is 38cm and the length of its diagonal is 22cm. Find the surface area of cuboid.

Answer 1

l+b+h = 38 cm
√$\sqrt{l ^{2} +b^{2} + h^{2}}$=22 cm


$\sqrt{ (l^{2} + b^{2} + h^{2} )}=22 cm$
$l^{2} +b^{2} + h^{2} =484 cm$
$(l+b+h) ^{2} -2lb-2bh-2hl=484 cm$
$38 ^{2} -(2lb+2bh+2hl)$=484
1444-484=2(lb+bh+hl)
960cm=2(lb+bh+hl)

as total surface area of a cuboid is 2(lb + bh+hl) , the total surface area of
this cuboid is 960 cm

Answer 2

We have given the sum of length, breadth and height=38cm and the length of the diagonal=22cm. We have it's surface area??