the sum of the length,the sum of the length breadth and the height of the cuboid is 22 cm and the length of the diagonal is 14 cm if the sum of cubes of the dimensions of the cuboid and we as its volume than what is [S- 3v] equal to
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Step-by-step explanation:
Let the length, breadth and height of the cuboid be L,B and H respectively.Given, L+B+H = 22 cm -(1)
Also, I presume here that the diagonal mentioned here in the question is the BODY DIAGONAL of the cuboid
(D) = sqrt (L^2 + B^2 + H^2) = 14 cm.Squaring both sides,(L^2 + B^2 + H^2) = 14^2 = 196 -
(2)Now, we know that (a+b+c)^2 = a^2 +
b^2 + c^2 + 2ab + 2bc + 2caSimilarly
,(L+B+H)^2 = L^2 + B^2 + H^2 + 2(LB + BH
+ LH)Using (1) and (2),22^2 = 196 + 2(LB +
BH + LH)Or 2(LB + BH + LH) = 484 - 196 =
Total surface area = 288 sq cm.
Hopes it help you♥️♥️
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