Question

The sum of the lengths of three ropes is 12 m. If one rope is 5 2 15 and another is 3 3 10 m long, find the length of the third rope?

Answer 1

Answer:

length of therhird rope = 4 7 11

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Answer 2

Answer:

3 17/30

Step-by-step explanation:

⇒Given

• The sum of the lengths of three ropes is 12 m

• One rope = 5 2/15

• Second rope = 3 3/10 m

• Third rope =  12 - 5 2/15 + 3 3/10

⇒Method

5 5/12 + 3 3/10 +   = 12 m

∴   = 12 - 5 2/15 + 3 3/10

Conversion into improper fraction

5 5/12 = 77/15

3 3/10 = 33/10

So, we have to do  

We have to find the LCM of denominators to find the sum of two fractions  

LCM= 30

77/15 x 2 = 154/30

33/10 x 3 = 99/30

⇒ 154/30 + 99/30 = 253/30

253/30 -12/1 =

253/30 - 360/30= 107/30

Now, we have to convert 107/30 into a mixed fraction

Conversion into mixed fraction

107/30 = 3 17/30

Verification

5 2/15 + 3 3/10 + 3 17/30 = 12 m

Conclusion

∴The length of the third rope is 3 17/30