the sum of the magnitude of two forces acting at apoint is 18 and the magnitude of their resultant is 12. if the resultant is at 90° with the force of smaller magnitude, what are the magnitude of forces?
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Let the magnitude of smaller force is P, the magnitude of larger force is Q and the resultant force is R.
As the resultant force makes 90
∘
with the smaller force P then Q forms the hypotenuse of the triangle.
Thus, it can be written as,
Q
2
−P
2
=R
2
Q
2
−P
2
=(12)
2
Q
2
−P
2
=144 (1)
The sum of magnitudes of two forces is given as,
P+Q=18
Q=18−P (2)
Substituting the value from equation (2) in equation (1), we get
(18−P)
2
−P
2
=144
P=5N
Substituting the value of P in equation (1), we get
Q=18−5
=13N
Thus, the magnitude of the forces are 5N and 13N.
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