The sum of the magnitude of two forces is 16 N. What are the forces if it is given that the resultant force is 8N and the resultant is perpendicular to the smaller force?
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The two forces are 10 N and 6N
Bcs when theta = 90° then
Resultant is always equal to
R=√(A^2+B^2)
Bcs when theta = 90° then
Resultant is always equal to
R=√(A^2+B^2)
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