Question

The sum of the magnitudes of two
forces acting at a point is 16 N. The
resultant of these forces is
perpendicular to the smaller force
and has a magnitude of 8 N. If the
smaller force is of magnitude x, then
the value of x is​

Answer 1

Explanation:

A+B=16...(1)

tanα=

A+Bcosθ

Bsinθ

=tan90

Thus, A+Bcosθ=0⇒cosθ=−

B

A

...(2)

We also have: 8=

A

2

+B

2

+2ABcosθ

...(3)

Solving these we get, A=6N and B=10N

Answer 2

Answer:

X=10N.....................