The sum of the 'n'term of an A.P. is 3n2+5n.find the A.P., hence find its 16th term.
moinu:
hai
Answers
Answered by
7
Tn = 3n^2+5n
n=1
T1 = a =
3×1+5×1
= 8
n=2
T2 = a+d
= 3×4 + 5×2
= 22
a = 8
d = 22-8 =14
hence the A.P will be ;
8,22,36,50,64...........
T16 = a+15d
= 8+15×14
= 218
hope this helped you ..... .... .... .. !!
n=1
T1 = a =
3×1+5×1
= 8
n=2
T2 = a+d
= 3×4 + 5×2
= 22
a = 8
d = 22-8 =14
hence the A.P will be ;
8,22,36,50,64...........
T16 = a+15d
= 8+15×14
= 218
hope this helped you ..... .... .... .. !!
solve :x+y= 8 and x-y=2
2x = 10 x=5 & y=3
Answered by
1
tn=3n2+5n
Taking n=1
t1=3(1)2+5(1)=6+5=11
Taking n=2
t2=3(2)2+5(2)=3(4)+10=12+10=22
Taking n=3
t3=3(3)2+5(3)=3(6)+15=18+15=33
So,Ap=11,22,33,...
To find 16th term i.e.n=16
Given in the given ap a=11,common difference(d)=10,n=16,tn=?
By formula,tn=a+(n-1)d
tn=11+(16-1)10
tn=11+15X10
tn=11+150
tn=161
Hence,16th term of the AP is 161.
Pls mark the answer as brainliest
Taking n=1
t1=3(1)2+5(1)=6+5=11
Taking n=2
t2=3(2)2+5(2)=3(4)+10=12+10=22
Taking n=3
t3=3(3)2+5(3)=3(6)+15=18+15=33
So,Ap=11,22,33,...
To find 16th term i.e.n=16
Given in the given ap a=11,common difference(d)=10,n=16,tn=?
By formula,tn=a+(n-1)d
tn=11+(16-1)10
tn=11+15X10
tn=11+150
tn=161
Hence,16th term of the AP is 161.
Pls mark the answer as brainliest
u hav done mistake. !!
what mistake
t1 = 3(1)2 + 5(1) = 3+5 = 8
hey,3X1X2=6.
U r wrong!
it's 3 multiply by one square ➕ 5
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