Question

the sum of the natural number from 1to n is 36 find n
​

Answer 1

Answer:

a=1,d=1

Sn=36

n/2[2a+(n−1)d]=36

n/2[2+(n−1)]=36

n[2+(n−1)]=72

n[n+1]=72

n^2+n−72=0

n^2+9n−8n−72=0

(n−8)(n+9)=0

∴n=-9,or n=8

plz mark as brainliest...I need it..if u mark, a hearty thanks to you