the sum of the natural numbers is 15 and the sum of their reciprocals is 3/10. find the numbers
Answers
Answered by
0
Answer:
hope it helps you
mark it as brainliest plz
Step-by-step explanation:
Let the two numbers are X and y
X+Y=15.....................(1)
SUMOF RECIPROCAL OF THAT TWO NUMBER=>1/X+1/Y=3/10
=>X+Y/XY = 3/10
=>X+Y = 3XY/10...........................(2)
SUBSTITUTE X+Y VALUE IN (2)
=>15*10 = 3XY
=>150 = 3XY
=>50=XY
=>Y=50/X..........................(3)
(3) IN (1)
X+50/X=15
X²+50=15X
X²-15X+50=0
X²-5X-10X+50=0
X(X-5)-10(X-5)=0
(X-10)(X-5)=0
X=10 AND X=5
SUBSTITUTE X VALUE IN (1)
10+Y=15 AND 5+Y=15
Y=5 AND Y=10
Similar questions