Question

The sum of the number and the spuare of the number is 32 then find the number

Answer 1

Let the number be x. Given,
$x + {x}^{2} = 32 \\ {x}^{2} + x - 32 = 0 \\ x = \frac{ - 1 + \: or \: - \sqrt{ {1}^{2} - 4 \times 1 \times - 32 } }{2 \times 1} \\ x = \frac{ - 1 + \: or \: - \sqrt{ 129 } }{2 }$