The sum of the number in gp is 28 and their product is 512. Find the numbers
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Step-by-step explanation:
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Secondary SchoolMath 10+5 pts
Find three numbers in G.P. such that their sum is 28 and their product is 512.
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Tanha7 ยท Ambitious
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Venkatavineela3 Virtuoso
Answer:
Step-by-step explanation:
Let the three numbers in GP be a/r,a,ar
sum=a/r+a+ar=28
product=a/r*a*ar=a^3=512
a^3=512
a^3=8^3
a=8
8/r+8+8r=28
8/r+8r=28-8=20
1/r+r=20/8
1/r+r=5/2
(1+r^2)/r=5/2
2+2r^2-5r=0
solving the quadratic equation
2r^2-5r+2=0
2r^2-4r-r+2=0
2r(r-2)-1(r-2)=0
r=2,1/2
now the terms are 8/2,8,8*2=4,8,16
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