Question

the sum of the number of a three digits number when divided by 9 gives a quotient of 2. find the number . the digit a,b,c are in the order of hundreds tens and ones respectively . the digits at the hundreds and tens place are 5 and 8 respectively . find the number and the digit at its unit place. plz plz plz give me solutions ​

Answer 1

Answer :-

As given

♦Sum of the digits of a three digit number is divisible by 9

The quotient = 2

♦The digits at

• Hundreds Place :- 5

• Tens Place :- 8

♦Now let us consider a number

100a + 10b + c

♦Sum of digits

a + b + c is divisible by 9

quotient = 2

→ Therefore sum of digits = 9 × 2

= 18

♦Now

→ 5 + 8 + c = 18

→ 13 + c = 18

→ c = 5

Now number

= 100(5) +10(8) + 5

= 500 + 80 + 5

= 585