Question

the sum of the number of two digits and the number formed by reversing the digit is 110 and the difference between the digit is 6 find the number​

Answer 1

Answer:

assuming the digits be x and y .

the number be 10x+y

so, number formed by reversing the digits be 10y+x

as given;

10x+y + 10y+x = 110

11x + 11y = 110

taking 11 as common

11( x + y ) = 110

x + y = 10

also;

x - y = 6. [ given ]

now solving both the equations.

we get;

2x = 16

x = 8

so,

8 + y =10

y = 2

so, the digits be 8 and 2.

Answer 2

$\huge\textbf{Answer:-}$

$\textbf{Let the digits be xand y respectively:-}$

$\textbf{10x+y is the Number :-}$

$\huge\textbf{Given:-}$

$=>10x+y +10y+x = 110$

$=>11x +11y = 110$

Let 11 be the common number:-

$=>11(x + y )= 110$

$=>x + y = 10$

$=>x - y = 6$

Equation:-

$=>2x = 16$

$=>x = 8$

$=>8 + y =10$

$=>y = 2$

$\textbf{8 and 2 are the digits:-}$