Question

The sum of the numbers from 300 to 700 which are divisible by 3 ? (300 and 700 are inclusive)

Answer 1

hey mate your answer is here ⬇️⬇️⬇️

here

first term(a1) = 300 (which is divisible by 3)

& last term = 699 (which is divisible by 3 )

commen difference (d) = 3

then we have to need find the number of terms; by arithmetic progression.

by using formula

An = A + (n-1)d

699 = 300 + dn-d

699 = 300 + 3n - 3

699 = 3n - 297

=>. 3n = 699 + 297

3n = 996

n = 996/3

n = 332

=> so the no. of terms are 332

that's mean 332 numbers are divisible by 3 between 300 and 700.

=> now we have need to find sum of numbers

by using formula

S = n/2(a+l) {where a is first term and l is last term}

S = 332/2(300+699)

S = 166(999)

S = 166 × 999

S = 165834

so that the sum of the numbers from 300 to 700 which are divisible by 3

hope it helps....and may be you have got a perfect answer..