Question

The sum of the numbers such that the mean proportional between them is 8 and third proportion to them is 16, is
a.24
b.28
c.20
d.12​

Answer 1

Given  :  three numbers such that the mean proportional between them is 8 and third proportion to them is 16

To Find : sum of the numbers

Solution:

Let say numbers are

a ,  8  , 16

as mean proportional between them is 8 and  third proportion to them is 16

8² = a * 16

=> a  = 4

Hence three numbers are

4 , 8 and 16

Sum = 4 + 8 +  16  = 28

Sum of  the numbers  is 28

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