Question

the sum of the numerator and denominatior of a fraction is 10 if both are increased by 1 thr fraction becomes eqal to 1/2 find the original form​

Answer 1

Answer:

ans is 3/7

hope this helps you

Answer 2

Answer:

$\frac{3}{7}$

Step-by-step explanation:

Let numerator be x and denominator be y

Their sumis 10

x+y=10                                                                                              -(1)

If both are increased by 1 (x+1; y+1) their fraction =$\frac{1}{2}$

$\frac{x+1}{y+1}$ = $\frac{1}{2}$

(x+1)2=(y+1)1

2x+2=y+1

2x-y=1-2

2x-y=-1                                                                                              -(2)

By elimination method

From equations (1) & (2)

               x+y=10

            + 2x-y=-1

               3x=9

                x=$\frac{9}{3}$

                x=3

By substituting the value of x in first equation

x+y=10

3+y=10

y=10-3

y=7

Hence, the original fraction is $\frac{3}{7}$

We can verify the answer

if we add 1 to both numerator and denominator

we get

$\frac{3+1}{7+1}$ = $\frac{4}{8}$ = $\frac{1}{2}$

Hope it helps

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