the sum of the numerator and denominator of a fraction is 3 less than twice the denominator. if the numerator and denominator decreased by , the number become half the denominator . determine the fraction
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[ Let the fraction be x/y
According to the question,
x + y + 3 = 2y
x = y - 3 ------(1)
Also, x-1/y-1 = y/2y = 1/2
x - 1 = (y-1) / 2
x = [ (y - 1) / 2 ] +1
x = (y +1) / 2
2x = y + 1
2x - y = 1 ------ (2)
Solving the both Equation;
2 ( y - 3 ) - y =1
2y - 6 -y = 1
y - 6 = 1
y = 7
x = y - 3
x = 7 - 3
x = 4]
Thanks!!
Anonymous:
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