Question

The sum of the numerator and denominator of a fraction is 3 less than twice the
denominator. If the numerator and denominator are decreased by 1, the numerator
becomes half the denominator. Determine the fraction.

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Answer 1

the numerator be 'x' and denominator be ' y'

then,

the sum of the numerator and denominator of a fraction is 3 less than the twice is x+y=2y-3 :- x-y+3=0 - equation 1

if the numerator and denominator is decreased by 1 then

x-1/y-1=1/2 :- 2(x-1) = 1(y-1) :- 2x-y-1=0 -equation 2

then equation 1 = equation 2

x-y+3=2x-y-1 :- x=4

from the equation 1 

x-y+3=0 :- 4-y+3=0 :- y=7

there fore the fraction is 3/7 

Answer 2

I hope you understand the answer thank you for your question