Question

The sum of the numerator and denominator of a fraction is 4 more than twice the numerator. If the numerator and denominator increased by 3, they are in the ratio 2:3. Determine the fraction.

Answer 1

Let the fraction be a/b
a+b=2a+4
a=b-4....(1)
a+3/b+3=2/3....(2)
Substitute (1) in(2)
b-4+3/b+3=2/3

By cancellation we get b=9
Substitute b in (1)
Thus (a,b)=(5,9)
...hence solved...