Question

The sum of the numerator and denominator of a fraction is 4 than twice the numerator. if the numerator and denominator are increased by 3 they are in the ratio 2:3 deter mine the fraction​

Answer 1

Let the required fraction be x/y .

As per the question

x + y = 4 + 2x

⇒ y – x = 4 ……(i)

After changing the numerator and denominator

New numerator = x + 3

New denominator = y + 3

Therefore x+3/ y+3 = 2/3

⇒3(x + 3) = 2(y + 3)

⇒3x + 9 = 2y + 6

⇒ 2y – 3x = 3 ……(ii)

Multiplying (i) by 3 and subtracting (ii), we get:

3y – 2y = 12 – 3 ⇒y = 9

Now, putting y = 9 in (i), we get:

9 – x = 4 ⇒ x = 9 – 4 = 5

Hence, the required fraction is 5/9

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Answer 2

Step-by-step explanation:

in an AP: if a=5 and d=1/4 write the first four terms