Question

The sum of the numerator and denominator of a fraction is 4 more than twice the numerator. If the numerator and denominator are increased by 3, they are in the ratio 2:3. Determine the fraction .

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Answer 1

5/9

x+y=2x+4

⇒y=x+4

x+3= 3/2

3x+9=2y+6⇒3x−2y=−3....eq2

Substitute the value of y

Answer 2

Step-by-step explanation:

Correct question:-

The sum of the numerator and denominator of a fraction is 4 more than twice the numerator. If the numerator and denominator are increased by 3, they are in the ratio 2:3. Determine the fraction ?

Correct answer:-

Let numerator =x and denominator= y

∴Fraction=yx

To find:-

According to the first condition:-

⇒x+y=2x+4

⇒y=x+4 .eqeation 1

According to the second condition

⇒y+3x+3=32

⇒3x+9=2y+6⇒3x−2y=−3.eq2

Substitute   the   value   of   y   from   eq1     to   eq2

⇒3x−2(x+4)=−3⇒3x−2x+8=−3⇒x=5

Put   x=5   in   eq1

⇒y=5+4⇒y=9

Hence,fraction=95

Required answer:- Fraction is 95

ANSWER:'

$95$

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