The sum of the numerator and denominator of a fraction is 8.if 3is added to both numerator and denominator the fraction becomes 3ââ4 find the fraction
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The answer is given below :
Let, the fraction be x/y, where y is non-zero.
Given, x + y = 8
=> 4x + 4y = 32 .....(i)
When 3 is add to both numerator and denominator, the fraction becomes
(x + 3)/(y + 3).
Given,
(x + 3)/(y + 3) = 3/4
=> 4x + 12 = 3y + 9
=> 4x - 3y + 3 = 0 .....(ii)
Subtraction between (i) and (ii) give :
7y = 35
=> y = 5
Putting y = 5 in (i), we get :
x = 3
Therefore, the required fraction is 3/5.
Thank you for your question.
Let, the fraction be x/y, where y is non-zero.
Given, x + y = 8
=> 4x + 4y = 32 .....(i)
When 3 is add to both numerator and denominator, the fraction becomes
(x + 3)/(y + 3).
Given,
(x + 3)/(y + 3) = 3/4
=> 4x + 12 = 3y + 9
=> 4x - 3y + 3 = 0 .....(ii)
Subtraction between (i) and (ii) give :
7y = 35
=> y = 5
Putting y = 5 in (i), we get :
x = 3
Therefore, the required fraction is 3/5.
Thank you for your question.
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