Question

the sum of the numerator and denominator of afraction is 12.if the denominator increased by 1 the fraction becomes 7/6.Find the fraction​

Answer 1

Answer:

The fraction is

$\frac{5}{7}$

Step-by-step explanation:

Let the required fraction be yx. Then,

x+y=12----------(1)

And, 

$\frac{x}{y + 3}$

=

$\frac{1}{2}$

2x−y=3 ---------(2)

On adding 1 and 2, we get,

x=5

On putting x=5 in equation 1, we get,

y=7

Therefore, the required fraction is 

$\frac{5}{7}$

Answer 2

Answer:

The fraction is 7/5

Step-by-step explanation:

Let the fraction be x/y

x+y=12 ------ equation (1)

x/y+1=7/6

=>6x=7y+7

=>6x-7y=7 ------- equation (2)

6(x+y=12)

=>6x+6y=72

1(6x-7y=7)

=>6x-7y=7

6x+6y=72

6x-7y= 07

(-) (+) (-)

___________

13y=65

=>y=65/13

=>y=5

x+y=12 {from eqn (1)}

=>x+5=12(y=5)

=>x=12-5

=>x=7

Therefore,the fraction =x/y=7/5