Question

the sum of the Numerator and denominator of
fraction is 4 more than twice of numerator
if Numerator and denominator are increased by 3
they are in Ratio 2:3 then find fraction,​

Answer 1

Answer:

Let numerator =x and denominator=y

∴Fraction=  

y

x

​  

 

According to the first condition

⇒x+y=2x+4

⇒y=x+4.....eq1

According to the second condition

⇒  

y+3

x+3

​  

=  

3

2

​  

 

⇒3x+9=2y+6⇒3x−2y=−3....eq2

Substitute   the   value   of   y   from   eq1     to   eq2

⇒3x−2(x+4)=−3⇒3x−2x+8=−3⇒x=5

Put   x=5   in   eq1

⇒y=5+4⇒y=9

Hence,fraction=  

9

5

​  

Step-by-step explanation:

Answer 2

Step-by-step explanation:

x+y = 4+2x

{x - y = -4 }×2

2x-2y = -8_______1

x+3/y+3 = 2/3

3x+9= 2y+6

3x -2y = -3_______2

-x = -5

x = 5

15 -2y= -3

2y = 18

y= 9

fraction = 5/9 answer