Question

The sum of the numerator and denominator of the fraction is one more than twice the numerator. If the numerator and denominator are increased by three, they are in the ratio 2:3. Find the fraction

Answer 1

x+y=2x+1
=x-2x+y=1
=-x+y=1                          ⇒    equation 1

x+3/y+3 =2/3
3(x+3)=2(y+3)
3x+9=2y+6
3x-2y=6-9
3x-2y=-3                             ⇒    equation 2

equation 1 × 3 ⇒-3x+3y=3
equation 2 × 1 ⇒3x-2y=-3
                          ⇒y=3-3=0    ⇒y=0

-x+y=1
-x+0=1
-x=1
x=-1 ⇒ -1/0 is the required fraction,

checking,....

   x+y=2x+1
 -1+0=-2+1
      -1=-1
L.H.S=R.H.S    and

x+3/y+3=2/3
-1+3/0+3=2/3
2/3=2/3
L.H.S=R.H.S 
                                         hope it helps, if possible mark as brainliest!