Question

The sum of the numerator and denominator of the fraction is 3 less than twice the
denominator. If the numerator and denominator are decreased by 1 then its resultant value is 1/2.Form a pair of linear equations and solve.​

Answer 1

Step-by-step explanation:

$let \: denominator \: be \: x$

$numerator + x = 2x - 3 \\ numerator = 2x - x -3 \\ numerator = x - 3$

A/Q

$\frac{x - 3 - 1}{x - 1} = \frac{1}{2}$

$2 \times (x - 4) = x - 1$

$2x - 8 = x - 1$

$2x - x = 8 - 1$

$x = 7$

$numerator = 7 - 3 = 4\\ denominator = 7$

$fraction = \frac{4}{7}$